Test on Monday!
You should spend time this weekend preparing for your test. Split time equally between Saturday and Sunday. Use the Review at the end of Chapter 2 for additional practice.
AMC 8 questions:
1. How many different four-digit numbers can be formed by rearranging the four digits in 2006?
(a) 4 (b) 6 (c) 16 (d) 24 (e) 81
2. The average of the five numbers in a list is 54. The average of the first two numbers is 48. What is the average of the last three numbers?
(a) 55 (b) 56 (c) 57 (d) 58 (e) 59
7 comments:
Hello again Mrs. Burke!
I will study hard this weekend for the test Monday, however, I'm dreading the day for the AMC math test. I don't understand how to figure the second problem out at all on the blog, and I have a little confusion with the first question. I don't think it would be 4! because you're trying to rearrange the digits, not a problem like Mt. Rushmore. But this problem is closely related to problem 25 in the AMC packet, where it says there are 24 ways to arrange these four digits. But since there are two zeros, could you say that 2006 and 2006 (switching the zeros) would be different numbers, or the same? I don't think you would do 4^4 because that results in a really high number, and you can only choose each digit once. I tried writing all the solutions out and came up with 11 different ways, (not switching the zeros as different numbers)which isn't an answer choice. Would the answer be 4*4=16? I'll see you tomorrow.
AMS
Hi Mrs. Burke,
I don't understand the questions you wrote on the blog. I'll ask you today.
-wiesej
Hi Mrs. Burke,
I'm leaving for Rehoboth thios weekend so I won't be able to comment later on...I am going to bring my math work though, don't worry!
I am pretty erady for the test, I just need a little more practice on the rate factor model for mult.
See you on Monday!
-wiesej
Wouldn't the answer to #1 of the blog questions be 4! which is 24, to answer ams' question.
Mrs. Burke,
I checked all my solutions for #1 on the blog and I found twelve different rearrangements without switching the zeros.
2006
2060
2600
0602
0620
0260
0206
0062
0026
6200
6020
6002
Shouldn't the answer be twelve? Good thing this is not on the test, I'll go over it with you again on Monday.
Have a good weekend!
AMS
The answer to question 1 is 24, I can't remember what letter of multiple choice this is. I have not figured out the second question yet, but I do not have time to figure it out right now. I'll try it in the morning!:)
KES
Both answers are (d) I think. It took me about two minutes with a calculator. I thought 1. is easy because I think the answer is 4! which is 24. 2 was harder, until I tried 48 + 48 + (e) + (e) + (e), then ans / 5. I worked backwards through the answer choices because I thought that you would need a higher average to even the averege out to 54. I hope I am right. See you tomorrow!
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